SSC CHSL 8-Jan-2017 Shift 1 Paper

Slope of line 2x + 3y = 6 is (−

2

3

)
Product of slopes of two perpendicular lines = -1
Let slope of line passing through origin = m
⇒ m×−

2

3

=−1
⇒ m=

3

2

Equation of line passing through origin and having slope m is (Since y intercept is zero)
⇒ y=

3

2

x
⇒ 3x=2y
Solving the above equations, we get the intersection point M = (

6

11

,

9

11

)