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SSC CHSL 9 Jan 2017 Shift 1 Paper

Question : 61 of 100

Marks: +1, -0

If cot(A + B) = x, then value of x is

Solution:

Expression : cot(A + B) = x

\frac{\sin(A+B)}{\cos(A+B)}

\frac{\sin A\cos B+\cos A\sin B}{\cos A\cos B-\sin A\sin B}

Dividing both numerator and denominator by , we get :

\frac{\cos A\cos B-\sin A\sin B}{\sin A\sin B}

\div \frac{\sin A\sin B+\cos A\cos B}{\sin A\sin B}

\left(\frac{\cos A\cos B}{\sin A\sin B}-1\right)

\div \left(\frac{\cos B}{\sin B}+\frac{\cos A}{\sin A}\right)

\frac{\cot A\cot B-1}{\cot B+\cot A}

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