4(l+b+h)=112 ⇒ (l+b+h)=28 and 2(lb+bh+hl)=384 ⇒ lb+bh+hl=192 we know, (l+b+h)2=l2+b2+h2+2lb+2bh+2hl ⇒ l2+b2+h2=(l+b+h)2−2(lb+bh+hl) ⇒ l2+b2+h2=(28)2−384 =784−384 =400 The relation between the radius of the sphere and the dimensions of the rectangular box is that ‘diagonal of rectangular box will be diameter of sphere’. ⇒ 2r=(l2+b2+h2)