The direction in which Shyam travels is represented as below:
In triangle ACB and triangle CDE, Angle B = angle D = 90° Angle ACB = angle DCE (Vertically opposite angles) AB = DE (Given) Hence, triangle ACB is congruent to triangle ECD. Thus, CD = BC =
BD
2
= 4.5 Using Pythagoras theorem , we find that CE = 7.5 Similarly, AC = 7.5 AE = CA + CE AE = 15 m