Let the age of the youngest child be x.Then, the ages of 6 children can be written as x, (x + 2), (x + 4), (x + 6) ,(x + 8) and (x + 10).x + (x + 2) + (x + 4) + (x + 6) + (x + 8) + (x +10) = 54⇒ 6x + 30 = 54⇒ 6x = 24⇒ x = 4Then, the second youngest child is (x + 2) = (4 + 2) = 6 years