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SSC CHSL Model Paper 3

Question : 50 of 100

Marks: +1, -0

Solution:

The stack is in the form having vertical cross section of trapezium.

∴ Volume of Earth in the stack = Area of cross section of trapezium × Height

∴ Volume

=\frac{1}{2}\times(10+5)\times2\times8

=15\times 8 \text{ m}^2

According to the question,

Volume of Earth to be spread = (Area of field) × Level raised

∴ Level raised

=\frac{15\times8}{100\times80}=\frac{15}{1000}

= 1.5 cm

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