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SSC CPO Tier 1 Exam 9 Dec 2025 Shift 1

Section: Quantitative Aptitude

Question : 111 of 200

Marks: +1, -0

Simplify:

\left(2\frac{1}{4}\times 1.6\right)+\left(1\frac{1}{3}\div0.4\right)

Solution:

Concept:

Convert mixed fractions to improper fractions, then simplify using basic arithmetic operations.

Explanation:

Convert the mixed fractions:

2\frac{1}{4} = \frac{9}{4}

and

1\frac{1}{3} = \frac{4}{3}

The expression becomes:

\left(\frac{9}{4} \times 1.6\right) + \left(\frac{4}{3} \div 0.4\right)

Compute the first term:

\frac{9}{4} \times 1.6 = \frac{14.4}{4} = 3.6

For the second term, write

0.4 = \frac{2}{5}

. Then

\frac{4}{3} \div \frac{2}{5} = \frac{4}{3} \times \frac{5}{2} = \frac{20}{6} = \frac{10}{3} \approx 3.33

Add the results:

3.6 + 3.33 = 6.93

Answer:

D. 6.93

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