Concept:In ratio problems, we substitute the terms using a common multiplier k.Explanation:Given x:y=3:2. Let x=3k and y=2k, where k is a constant.Then the expression becomes 3x+7y2x+5y​=3(3k)+7(2k)2(3k)+5(2k)​.Simplify numerator: 6k+10k=16k.Simplify denominator: 9k+14k=23k.So the fraction is 23k16k​=2316​ (since k cancels).Thus the required value is 2316​.Answer:Option D: 2316​.