SSC CPO Tier 1 Exam 9 Dec 2025 Shift 2

Section: Quantitative Aptitude

Question : 113 of 200

Marks: +1, -0

Expand : (2x - 3)^{2}

Solution:

Concept:

Use the algebraic identity

(a - b)^{2} = a^{2} - 2ab + b^{2}

to expand a binomial square.

Explanation:

Here,

a = 2x

and

b = 3

First, square the first term:

(2x)^{2} = 4x^{2}

Then, compute twice the product:

2 \times (2x) \times 3 = 12x

Finally, square the second term:

3^{2} = 9

Combine them with the correct signs:

4x^{2} - 12x + 9

Answer:

Option B:

4x^{2} - 12x + 9

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