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SSC GD Constable 4 Feb 2025 Shift 2 Paper

Section: Elementary Mathematics

Question : 56 of 80

Marks: +1, -0

If 7A = 6B = 12C, what is A : B : C?

Solution:

To find the ratio

A : B : C

, we can equate each term to a common variable and solve for

A , B

, and C .

Calculations:

Let

7 A = 6 B = 12 C = k

Then,

A = \frac{k}{7}

B = \frac{k}{6}

C = \frac{k}{12}

A : B : C = \frac{k}{7} : \frac{k}{6} : \frac{k}{12}

To remove the fractions, multiply each term by the LCM of the denominators

(7,6,12)

, which is 84.

A : B : C = \left(\frac{k}{7}\right) \times 84 : \left(\frac{k}{6}\right) \times 84 : \left(\frac{k}{12}\right) \times 84

A : B : C = 12 k : 14 k : 7 k

Since ' k ' is common, we can eliminate it.

A : B : C = 12 : 14 : 7

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