SSC GD Constable 4 Feb 2025 Shift 3 Paper

Let the original price of fuel be ₹100.
After the first month (40\% decrease):
Price after 40% decrease =100×(1−40∕100)=100×0.60=₹60
After the second month (10\% decrease):
Price after 10% decrease =60×(1−10∕100)=60×0.90=₹54
After the third month (50\% decrease):
Price after 50\% decrease =54×(1−50∕100)=54×0.50=₹27
After the fourth month (50\% increase):
Price after 50\% increase =27×(1+50∕100)=27×1.50=₹40.5
Percentage change =[( Final Price - Original Price )∕ Original Price ]×100
Percentage change =[(40.5−100)∕100]×100
Percentage change =(−59.5∕100)×100=−59.5%