Work done on the 1 st day (2 men +6 women )=(1∕10)+(1∕5)=(1∕10)+(2∕10)=3∕10 Work done on the 2 nd day (5 boys +6 women )=(1∕10)+(1∕5)=(1∕10)+(2∕10)=3∕10 Work done in 2 days =(3∕10)+(3∕10)=6∕10=3∕5 Remaining work after 2 days =1−3∕5=2∕5 Work done on the 3 rd day (2 men +6 women )=3∕10 Remaining work after 3 days =2∕5−3∕10=4∕10−3∕10=1∕10 Work done on the 4 th day (5 boys +6 women )=3∕10 Work completed on the 4th day itself. ⇒ The work is finished in 3(1∕3) days.