SSC MTS 4 Feb 2026 Shift 3 Paper

Concept:Compare two recurring decimals by expanding them into infinite sequences and checking digits from left to right.Explanation:First, write the target value $0.\bar{72}$ as $0.727272\ldots$ .Now expand each option:Option A: $0.7\bar{1} = 0.711111\ldots$Option B: $0.7\bar{3} = 0.733333\ldots$Option C: $0.\bar{70} = 0.707070\ldots$Option D: $0.\bar{71} = 0.717171\ldots$Compare the digits starting from the tenths place: all have $7$ in tenths, so move to the hundredths place.Target has $2$ in hundredths. Option A has $1$, Option B has $3$, Option C has $0$, Option D has $1$.Only Option B has a hundredths digit ($3$) greater than $2$, so $0.7333\ldots > 0.7272\ldots$.Thus, only $0.7\bar{3}$ is greater than $0.\bar{72}$.Answer:Option B: $0.7\bar{3}$