SSC MTS 5 Aug 2019 Shift 3 Paper

Follow BODMAS rule to solve this question, as per the order is given below: Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first and in the bracket, Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next, Step-3: Next, the parts of the equation that contains ‘Division’ and ‘Multiplication’ are calculated, Step-4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated. Given expression is,⇒ $\frac{ \frac{3}{4} \div \frac{9}{32} + \frac{4}{3} \times \frac{2}{3} \text{of} \frac{27}{16} }{ \frac{1}{2} \times \left( \frac{8}{3} - 2 \right) \div \frac{4}{9} \left( \frac{1}{3} + \frac{1}{6} \right) }$ ⇒ $\frac{ \frac{3}{4} \div \frac{9}{32} + \frac{4}{3} \times \frac{2}{3} \text{of} \frac{27}{16} }{ \frac{1}{2} \times \frac{2}{3} \div \frac{4}{9} + \frac{1}{2} }$ ⇒ $\frac{ \frac{3}{4} \div \frac{9}{32} + \frac{4}{3} \times \frac{9}{8} }{ \frac{1}{2} \times \frac{2}{3} \div \frac{4}{9} + \frac{1}{2} }$ ⇒ $\frac{ \frac{8}{3} + \frac{4}{3} \times \frac{9}{8} }{ \frac{1}{2} \times \frac{3}{2} + \frac{1}{2} }$ ⇒ $\frac{ \frac{8}{3} + \frac{3}{2} }{ \frac{3}{4} + \frac{1}{2} }$ ⇒ $\frac{ \frac{25}{6} }{ \frac{5}{4} }$ ⇒ 10/3