Concept:This problem uses circular seating arrangement logic. Conditions define relative positions; we place persons step by step around the circle.
Explanation:There are 7 seats arranged in a circle. Place D at a starting point. Since C is fifth to the left of D, moving five steps counterclockwise from D gives C. In a circle of 7, this means C is two steps clockwise from D.
Next, C has two immediate neighbours – B and Y. So B and Y sit on either side of C.
A is immediate neighbour of both Z and D. The only seat next to D that is not already taken by B or Y is the other side of D. So A sits on the far side of D, and Z sits next to A away from D.
Now the only empty seat left is for X. Place X there.
Finally, apply the condition that B is not an immediate neighbour of X. Check both possibilities: B must be placed so that X is not next to B. This forces B to be on the side opposite to X. The arrangement becomes: D, B, C, Y, X, Z, A in clockwise order.
Count fourth to the left of B. Going counterclockwise from B: first left is D, second is A, third is Z, fourth is X.
Answer:X (Option B)
