Concept:This is a circular seating arrangement problem. Use the given relative positions to place the girls, then apply the restrictions to find the count between G4 and G6.
Explanation:Put G3 at a fixed point. G6 is second to the left of G3, so G6 is two steps anticlockwise from G3.
G1 is third to the right of G3, so G1 is three steps clockwise from G3.
G7 is third to the right of G6, so from G6 go three steps clockwise to place G7.
Now we have positions for G3, G6, G1, G7. The remaining girls are G2, G4, G5.
G2 cannot be next to G1. G4 cannot be next to G6.
Arrange the remaining girls while respecting these rules. The final order (clockwise) becomes: G3, G2, G4, G1, G5, G6, G7 (starting from G3).
From the left of G4 (anticlockwise), count the girls between G4 and G6. The sequence from G4 leftwards: G2, G3, then G6? Actually, going left from G4 means anticlockwise direction. In the order, anticlockwise from G4: G2, G3, then G6? Wait, let's check carefully. The clockwise order given: G3, G2, G4, G1, G5, G6, G7. So anticlockwise from G4 goes: G2, G3, then G6? Actually after G3 anticlockwise would be G7? Need to confirm arrangement. Better to draw: Let positions be numbered 1 to 7 clockwise. Place G3 at 1. Then G6 is second left of G3 -> anticlockwise two steps: position 6 (if numbering clockwise 1 to 7). Then G1 third right of G3 -> clockwise three steps: position 4. Then G7 third right of G6 -> from G6 at position 6, clockwise three steps: position 2. Now filled: pos1=G3, pos2=G7, pos4=G1, pos6=G6. Remaining positions 3,5,7 for G2,G4,G5. G2 not next to G1 (pos4) -> G2 cannot be at pos3 or pos5. So G2 must be at pos7. G4 not next to G6 (pos6) -> G4 cannot be at pos5 or pos7. So G4 cannot be at pos5 or pos7, thus G4 must be at pos3. Then G5 goes to pos5. Final clockwise order: pos1=G3, pos2=G7, pos3=G4, pos4=G1, pos5=G5, pos6=G6, pos7=G2. Now "towards left of G4" means anticlockwise direction from G4. From pos3, anticlockwise direction goes: pos2 (G7), pos1 (G3), pos7 (G2), pos6 (G6). So between G4 and G6, going left from G4, we pass G7, G3, G2 – that's 3 girls. Hence there are 3 girls between them.
Answer:C. 3
