The force in SHM is F=−kx The maximum force is Fmax=−kA Given, F=0.866F‌max ‌ So, −kx‌=0.866(−kA) x‌=0.866A The velocity in SHM is v=ω√(A2−x2) ‌v=ω√A2−(0.866A)2 ‌v=ω√A2−0.75A2=ω√0.25A2 ‌v=ω(0.5A) The maximum velocity in SHM occurs at x=0, So vmax=ωA The ratio is ‌
v
vmax
=‌
0.5ωA
ωA
‌
v
vmax
=0.5=‌
1
2
The ratio of its velocity at that point and its maximum velocity is ‌