)+2sin‌2θ=0 ‌⇒8+3+3‌cos‌2‌θ+4sin‌2θ=0 ‌⇒11+3‌cos‌2‌θ+4sin‌2θ=0 This equation has no solution because the maximum value of 4sin‌2θ+3‌cos‌2‌θ is 5 . Since 5+11≠0, there is no value of θ that satisfies the equation.