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Time and Distance Practice Test 3 with solutions
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© examsnet.com
Question : 4
Total: 40
A and B travel around a circular park at uniform speeds in opposite directions, starting from diametrically opposite points, at the same time. They meet each other first after B has travelled 100 meters and meet again 60 meter before A completed one round. The circumference of the park is:
240 m
300 m
320 m
480 m
Validate
Solution:
Time taken by B =
100
x
second
Time taken by A =
100
x
second
Distance covered by A =
100
x
× y
=
100
(
y
x
)
m
Circumference =
2
[
100
+
(
100
y
x
)
]
=
200
(
1
+
y
x
)
... (i)
Distance covered by B =
100
(
y
x
)
x
+
60
=
200
(
1
+
y
x
)
−
60
−
100
(
y
x
)
y
y
[
100
(
y
x
)
+
60
]
=
x
[
200
+
200
(
y
x
)
−
60
−
100
y
x
]
100
y
2
x
= 200x + 200y - 60x - 100y
100
y
2
x
+
60
y
= 140x + 100y
100
y
2
x
= 140x + 40y
10
y
2
=
14
x
2
+
4
y
x
5
y
2
=
7
x
2
+
2
x
y
5
(
y
x
)
2
=
7
+
2
(
y
x
)
Let
y
x
= t
5
t
2
- 2t - 7 = 0
5t 2- 7t + 5t - 7 = 0
(5t + 7) (t + 1) = 0
t(5t - 7) + 1 (5t - 7)
t = -1 not possible
t =
7
5
Substituting value of t in equation (i),
200
(
1
+
7
5
)
=
200
(
12
5
)
= 480 m
© examsnet.com
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