Time and Distance Practice Test 4 with solutions

Distance covered by ball just before it hits the ground for the first time = 120 feet
In the second round, the distance covered by the ball = (120×

4

5

)×2
In the third round, the distance covered by the ball = 120×(

4

5

)2×2
In the fourth round, the distance covered by the ball = 120×(

4

5

)2×2
Hence, the required distance :
=
= 120+2×120[

4

5

+

16

25

+

64

125

+...]
= 120 + 240[

4 5

1− 4 5

]
= 120 + 240[

4

5

×

5

1

]
= 120 + 960 = 1,080 metres