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TS EAMCET 04 May 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 106
Total: 160
A metal plate of thickness 2 mm and area 36 π
c
m
2
is slid into a parallel plate capacitor of plate spacing 6 mm and area 36 π
c
m
2
. The metal plate is at a distance 3 mm from one of the plates. What is the capacitance of this arrangement?
(Let
1
4
π
∊
0
= 9 ×
10
9
N
m
2
C
−
2
)
8 pF
15 pF
25 pF
20 pF
Validate
Solution:
Consider the below diagram.
The circuit can be derawn as,
The equivalent of the above circuit is calculated as
C
e
q
=
C
1
C
2
C
1
+
C
2
Substitute
ε
0
A
d
1
for
C
1
and
ε
0
A
d
2
for
C
2
. in the above equation.
C
e
q
=
ε
0
A
[
1
d
1
×
1
d
2
1
d
1
+
1
d
2
]
=
ε
0
A
d
1
+
d
2
Substitute the given values in the above equation.
C
e
q
=
1
4
π
×
9
×
10
9
×
36
π
×
10
−
4
3
×
10
−
3
+
1
×
10
−
3
=
1
4
×
10
−
10
=
25
p
F
© examsnet.com
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