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TS EAMCET 10-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 144
Total: 160
25 mL of 0.1 N NaOH solution neutralizes 12.5 mL of HCl solution. The amount of water needed to convert 500 mL of such HCl solution to 0.1 N is
555 mL
500 mL
50 mL
55.5 mL
Validate
Solution:
∵
Concentration of
N
a
O
H
(
N
1
)
=
0.1
N
Volume of
N
a
O
H
used
(
V
1
)
=
25
m
L
Concentration of
H
C
l
(
N
2
)
=
0.1
N
Volume of
H
C
l
(
V
2
)
used
=
V
2
and
N
1
V
1
=
N
2
V
2
Thus,
V
2
=
N
1
V
1
N
2
=
0.1
×
25
0.1
Volume of
H
C
l
used
(
V
2
)
=
25
m
L
=
V
1
Thus, to convert
500
m
L
H
C
l
solution to
0.1
N
H
C
l
,
we need
500
m
L
of water.
Hence, option (b) is the correct answer.
© examsnet.com
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