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TS EAMCET 11-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 110
Total: 160
The ratio o f the magnetic field inside a solenoid at an axial point well inside and at an axial end point is
2
1/2
1
3/2
Validate
Solution:
The magnetic field at some internal point on the axis of a solenoid is given by
B
=
µ
0
n
I
2
(
cos
θ
1
−
cos
θ
2
)
Magnetic field at the centre of a long solenoid is given by setting
θ
1
=
0
∘
and
θ
2
=
π
.
⇒
B
1
=
µ
0
n
I
2
(
cos
0
∘
−
cos
π
)
=
µ
0
n
I
2
[
1
−
(
−
1
)
]
=
µ
0
n
I
..(i)
Similarly, the magnetic field at the end of a long solenoid is given by setting
θ
1
=
π
2
and
θ
2
=
τ
⇒
B
2
=
µ
0
n
I
2
(
cos
π
2
−
cos
π
)
=
µ
0
n
I
2
[
0
−
(
−
1
)
]
=
µ
0
n
I
2
...(ii)
From Eq. (i) and Eq. (ii), we get
B
1
B
2
=
µ
0
n
I
µ
0
n
I
×
2
=
2
© examsnet.com
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