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TS EAMCET 11-Sep-2020 Shift 2 Solved Paper
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© examsnet.com
Question : 99
Total: 160
A gas is at constant pressure
4
×
10
5
N
/
m
2
. When a heat energy of 2000 J is supplied to the gas, its volume changes by
3
×
10
−
3
m
3.
What is the increase in its internal energy?
650 J
900 J
800 J
400 J
Validate
Solution:
Given, pressure,
p
=
4
×
10
5
N
/
m
2
,
∆
Q
=
2000
J
Change in volume,
∆
V
=
3
×
10
−
3
m
3
Now, the work done to change volume is
∆
W
=
p
∆
V
=
4
×
10
5
×
3
×
10
−
3
=
12
×
10
2
=
1200
J
According to first law of thermodynamics,
So, change in internal energy,
∆
U
=
∆
Q
−
∆
W
=
2000
−
1200
=
800
J
© examsnet.com
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