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TS EAMCET 14-Sep-2020 Shift 1 Solved Paper
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© examsnet.com
Question : 143
Total: 160
pH of 0.05M aqueous solution of diethyl amine is 10. The value of equilibrium constant is
4
×
10
−
7
2
×
10
−
7
2
×
10
−
3
4
×
10
−
3
Validate
Solution:
(
C
2
H
5
)
2
N
H
(
1
−
α
)
C
+
H
2
O
excess
⇌
⊖
O
H
α
C
+
(
C
2
H
5
)
2
⊕
N
H
2
α
C
Equilibrium constant,
K
=
α
C
×
α
C
(
1
−
α
)
C
=
α
2
C
(
1
−
α
)
∼
e
q
α
2
C
[
∵
α
<
<
1
]
⇒
K
=
α
2
C
=
(
2
×
10
−
3
)
2
×
0.05
=
2
×
10
−
7
[Given :
p
H
=
10
so,
p
O
H
=
4
⇒
[
O
H
−
]
=
α
C
=
10
−
4
M
⇒
α
=
10
−
4
0.05
=
2
×
10
−
3
As,
C
=
0.05
M
(given)]
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