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Test Index
TS EAMCET 14-Sep-2020 Shift 1 Solved Paper
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© examsnet.com
Question : 37
Total: 160
A person tossing a biased coin indefinitely wins the game by getting head for the first time. The probability that he wins the game in odd number of tosses is
3
4
.If 5 such coins are tossed at a time then the probability that head appears on all the coins is
32
3125
243
3125
1
243
32
243
Validate
Solution:
Let the probability getting head
=
p
probability of not getting head
=
1
−
p
Given, he wins the game in odd number of tosses
∴
p
+
(
1
−
p
)
2
p
+
(
1
−
p
)
4
p
+
.
.
.
=
3
4
p
1
−
(
1
−
p
)
2
=
3
4
4
p
=
3
−
3
(
1
−
2
p
+
p
2
)
=
6
p
−
3
p
2
3
p
2
=
2
p
⇒
p
=
2
3
5 coins are tossed at a time the probability of head appears is
5
C
5
(
2
3
)
5
=
32
343
© examsnet.com
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