We have kx2+8xy−3y2+2x−4y−1=0 is form of a straight line ∴|
k
4
1
4
−3
−2
1
−2
−1
|=0
k(3−4)−4(−4+2)+1(−8+3)=0
−k+8−5=0⇒k=3 ∴ Acute angle between line joining the origin α the point of intersection x+y=1 and line 3x2+8xy−3y2+2x−4y−1=0 by Homogenous using the equation