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TS EAMCET 18-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 100
Total: 160
If the root mean square (rms) speed of nitrogen molecules at room temperature is
100
m
∕
s
, then the rms speed of Helium molecule at the same temperature is
100
√
7
m
∕
s
350
m
∕
s
50
√
14
m
∕
s
100
m
∕
s
Validate
Solution:
Wé know,
v
rms
=
√
3
R
T
M
(where
M
=
molar mass of gas)
For
N
2
:
⇒
100
=
√
3
R
T
×
1000
28
(for
N
2
molar mass,
M
=
28
1000
kg
)
⇒
100
=
√
3000
R
T
28
⋅
⋅
⋅
⋅
⋅
⋅
⋅
(
i
)
Now,
for He,
v
rms
′
=
√
3
R
T
×
1000
4
(for He molar mass,
M
=
4
100
kg
)
i.e
v
rms
′
=
√
3000
R
T
4
⋅
⋅
⋅
⋅
⋅
⋅
⋅
(
i
i
)
Dividing Eq. (ii) by Eq. (i), we get
v
rms
′
100
=
√
3000
R
T
4
3000
R
T
28
⇒
v
rms
′
100
=
√
28
4
⇒
v
rms
′
=
100
√
7
m
∕
s
© examsnet.com
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