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TS EAMCET 18-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 11
Total: 160
If the extreme value of
3
x
−
2
x
2
+
1
is
k
then the set of all real values of
x
for which
k
x
2
+
2
x
+
1
>
0
is
(
1
2
,
1
)
(
−
∞
,
1
2
)
∪
(
1
,
∞
)
(
−
∞
,
∞
)
(
−
∞
,
17
8
)
None of above
Validate
Solution:
👈: Video Solution
(*) Let
f
(
x
)
=
3
x
−
2
x
2
+
1
Given, extreme value of
f
(
x
)
is
k
.
⇒
f
′
(
k
)
=
0
3
−
2
(
2
k
)
=
0
k
=
3
∕
4
∵
k
x
2
+
2
x
+
1
>
0
⇒
3
4
x
2
+
2
x
+
1
>
0
⇒
3
x
2
+
8
x
+
4
>
0
⇒
(
x
+
2
3
)
(
x
+
2
)
>
0
⇒
x
∈
(
−
∞
,
−
2
3
)
∪
(
−
2
,
∞
)
© examsnet.com
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