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TS EAMCET 18-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 141
Total: 160
Iron crystalizes in FCC with an edge length of
400
p
m
. If it contains
0.1
%
Schottky defects, calculate its approximate density
[
A
W
of
F
e
=
56
g
∕
m
o
l
]
5.8
g
∕
c
m
3
1.5
g
∕
c
m
3
2.9
g
∕
c
m
3
8.5
g
∕
c
m
3
Validate
Solution:
The density is given by
ρ
=
Z
×
M
N
A
×
a
3
Since their is
0.1
%
Schottky defect, so the
Z
value will change.
Z
=
4
−
4
×
0.1
100
=
3.996
Putting this value of
Z
in above equation
ρ
=
3.996
×
55.8
g
6.023
×
10
23
×
(
400
×
10
−
10
cm
)
3
=
5.8
g
cm
−
3
.
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