Given in bag containing 5 black balls and 3 white balls. Random variable X denotes the number of white balls drawn X(0)= No white ball is drawn P(0)=‌
‌3C0×‌5C2
‌8C2
=‌
10
28
X(l)=1 white ball is drawn P(X)‌=‌
‌5C1×‌3C1
‌8C2
=‌
15
28
X(2)‌=2‌ white balls are drawn ‌ P(X)‌=‌