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TS EAMCET 18-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 4
Total: 160
|
1
1
1
a
2
b
2
c
2
a
3
b
3
c
3
|
=
a
2
b
2
(
a
−
b
)
+
b
2
c
2
(
b
−
c
)
+
c
2
a
2
(
c
−
a
)
a
2
(
b
3
−
c
3
)
+
b
2
(
c
3
−
a
3
)
+
c
2
(
a
3
−
b
3
)
a
3
(
b
2
−
c
2
)
+
b
3
(
c
2
−
a
2
)
+
c
3
(
a
2
−
b
2
)
a
b
(
a
3
−
b
3
)
+
b
c
(
b
3
−
c
3
)
+
c
a
(
c
3
−
a
3
)
Validate
Solution:
👈: Video Solution
Given,
|
1
1
1
a
2
b
2
c
2
a
3
b
3
c
3
|
=
(
b
2
c
3
−
b
3
c
2
)
−
(
a
2
c
3
−
a
3
c
2
)
+
(
a
2
b
3
−
a
3
b
2
)
=
(
a
2
b
3
−
a
2
c
3
)
+
(
b
2
c
3
−
a
3
b
2
)
+
(
a
3
c
2
−
b
3
c
2
)
=
a
2
(
b
3
−
c
3
)
+
b
2
(
c
3
−
a
3
)
+
c
2
(
a
3
−
b
3
)
© examsnet.com
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