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TS EAMCET 18-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 11
Total: 160
Let
f
(
x
)
=
6
x
2
−
18
x
+
21
6
x
2
−
18
x
+
17
. If
m
is the maximum value of
f
(
x
)
and
f
(
x
)
>
n
∀
x
∈
C
Then
14
m
−
7
n
=
-1
23
35
42
Validate
Solution:
👈: Video Solution
f
(
x
)
=
6
x
2
−
18
x
+
21
6
x
2
−
18
x
+
17
=
1
+
4
6
x
2
−
18
x
+
17
Now,
6
x
2
−
18
x
+
17
∈
[
7
2
,
∞
)
[
∵
a
x
2
+
b
x
+
c
∈
[
−
D
4
a
,
∞
)
when
a
>
0
]
∴
4
6
x
2
−
18
x
+
17
∈
(
0
,
8
7
]
∴
f
(
x
)
∈
(
1
,
15
7
]
∴
m
=
15
7
and
n
=
1
⇒
14
m
−
7
n
=
30
−
7
=
23
© examsnet.com
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