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TS EAMCET 18-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 3
Total: 160
If
A
+
B
=
[
2
1
2
1
2
0
0
2
2
]
,
A
B
=
[
1
2
2
1
1
0
1
2
1
]
then
A
2
+
B
(
A
+
B
)
=
[
4
6
6
3
4
2
1
6
3
]
[
4
9
6
3
3
2
4
7
4
]
[
6
10
8
4
5
2
4
9
6
]
[
3
4
4
2
3
2
0
4
2
]
Validate
Solution:
👈: Video Solution
A
+
B
=
[
2
1
2
1
2
0
0
2
2
]
,
A
B
=
[
1
2
2
1
1
0
1
2
1
]
(
A
+
B
)
2
=
[
2
1
2
1
2
0
0
2
2
]
[
2
1
2
1
2
0
0
2
2
]
=
[
5
8
8
4
5
2
2
8
4
]
(
A
+
B
)
2
=
A
2
+
B
2
+
A
B
+
B
A
∴
A
2
+
B
2
+
B
A
=
(
A
+
B
)
2
−
A
B
or
A
2
+
B
(
A
+
B
)
=
[
5
8
8
4
5
2
2
8
4
]
−
[
1
2
2
1
1
0
1
2
1
]
=
[
4
6
6
3
4
2
1
6
3
]
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