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TS EAMCET 19-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 117
Total: 160
The radius and mass number of nucleus ' 1 ' is
R
1
and
A
1
respectively. The radius and mass number of nucleus ' 2 ' is
R
2
and
A
2
respectively. If
A
2
is larger than
A
1
by
2
%
, then
R
2
is larger than
R
1
by
2
3
%
1
%
8
%
3
2
%
Validate
Solution:
We know that, radius of nucleus in terms of mass number
(
A
)
is given as
R
=
R
0
(
A
1
∕
3
)
⇒
R
2
R
1
=
(
A
2
A
1
)
1
3
....(i)
But,
A
2
=
A
1
+
2
%
of
A
1
=
A
1
+
2
100
A
1
=
102
100
A
1
=
1.02
A
1
.
From Eq (i), we get
R
2
R
1
=
(
1.02
A
1
A
1
)
1
3
=
(
1.02
)
1
∕
3
R
2
=
R
1
(
1.02
)
1
∕
3
R
2
=
1.0067
R
1
=
R
1
+
0.0067
R
1
=
R
1
+
0.67
%
of
R
1
=
R
1
+
2
3
%
of
R
1
Hence,
R
2
is larger than
R
1
by
2
3
%
.
© examsnet.com
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