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TS EAMCET 19-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 90
Total: 160
A wheel of radius with
0.5
m
and a moment of inertia of
10
k
g
⋅
m
2
is rotating freely at an angular speed of
70
r
e
v
∕
m
i
n
. The wheel can be stopped in
5.0
s
by pressing a wet cloth against the rim and exerting a radially inward force of
88
N
. The coefficient of kinetic friction between the wheel and wet cloth is
0.17
0.33
0.40
0.60
Validate
Solution:
Radius of wheel,
R
=
0.5
m
Moment of inertia of wheel,
I
=
10
kg
−
m
2
Initial angular velocity
=
2
π
×
70
60
rad
∕
s
⇒
ω
0
=
14
π
6
rad
∕
s
t
=
5
s
, final angular velocity,
ω
=
0
Using equation of rotational motion,
ω
=
ω
0
+
α
t
⇒
α
=
ω
−
ω
0
t
=
0
−
14
π
6
5
=
14
π
30
rad
∕
s
2
∴
Torque on the wheel,
τ
=
I
α
=
10
×
14
30
π
=
14
π
3
N
−
m
⇒
τ
=
14
π
3
But torque on the wheel to stop it,
τ
′
=
F
×
R
=
88
×
0.5
=
44
N
−
m
Coefficient of kinetic friction between wheel and wet cloth,
µ
=
τ
τ
′
=
14
π
3
44
=
0.33
© examsnet.com
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