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TS EAMCET 19-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 41
Total: 160
If
A
(
1
,
1
)
,
B
(
−
1
,
1
)
and
C
(
−
1
,
−
1
)
are three points and a point
P
moves such that
P
A
2
=
P
B
2
+
P
C
2
, then the equation of the locus of
P
is
x
2
+
y
2
−
6
x
−
2
y
+
2
=
0
x
2
+
y
2
+
6
x
+
2
y
+
2
=
0
x
2
+
y
2
+
6
x
−
2
y
+
2
=
0
x
2
+
y
2
+
6
x
+
2
y
−
2
=
0
Validate
Solution:
Let the coordinate of point
P
be
(
h
,
k
)
.
(
P
A
)
2
=
(
h
−
1
)
2
+
(
k
−
1
)
2
(
P
B
)
2
=
(
h
+
1
)
2
+
(
k
−
1
)
2
(
P
C
)
2
=
(
h
+
1
)
2
+
(
k
+
1
)
2
(
P
A
)
2
=
(
P
B
)
2
+
(
P
C
)
2
(
h
−
1
)
2
+
(
k
−
1
)
2
=
(
h
+
1
)
2
+
(
k
−
1
)
2
+
(
h
+
1
)
2
+
(
k
+
1
)
2
⇒
h
2
−
2
h
+
1
=
h
2
+
2
h
+
1
+
h
2
+
1
+
2
h
+
k
2
+
2
k
+
1
⇒
h
2
+
k
2
+
6
h
+
2
k
+
2
=
0
Locus of point
P
is
x
2
+
y
2
+
6
x
+
2
y
+
2
=
0
© examsnet.com
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