Given, the equation of line 4x−6y−2=0 and the equation of curve
3x2−4xy+5y2−2x+y−6=0 The equation of line 4x−6y−2=0 can be written as 2x−3y=1 The equation of curve can be written as (3x2−4xy+5y2)−(2x−y)(1)−6(1)2=0 Now, substitute 1=2x−3y in equation of curve