Let after time t=01s, fired bullet reaches at point A. If v be the velocity and α be the angle made by displacement vector from horizontal at point A, then vcosα=ux=10√3 ⇒vcosα=10√3.....(i) and vsinα=usinθ−gt =uy−gt=10−10×0.1 ⇒vsinα=9......(ii) Dividing Eq. (ii) by Eq. (i), we get