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TS EAMCET 19-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 96
Total: 160
176
g
of
CO
2
can change its temperature from
0
∘
C
to
30
∘
C
by absorbing
3600
J
of thermal energy. Molar specific heat of
CO
2
(in
J
mol
−
1
K
−
1
) is
30
40
50
60
Validate
Solution:
Given, mass of
CO
2
,
m
=
176
g
Atomic mass of
CO
2
,
M
=
12
+
16
×
2
=
44
∴
Number of mole of
CO
2
n
=
m
M
=
176
44
=
4
Change in temperature,
∆
T
=
30
−
0
=
30
∘
C
=
30
K
Heat absorbed,
Q
=
3600
J
We know that,
Q
=
n
s
∆
T
⇒
3600
=
4
×
s
×
30
⇒
s
=
3600
30
×
4
=
30
J
mol
−
1
K
−
1
© examsnet.com
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