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TS EAMCET 20-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 99
Total: 160
When a gas expands adiabatically, its volume is doubled while its absolute temperature is decreased by a factor of 2 . The value of the adiabatic constant is
1
5
∕
3
2
7
∕
5
Validate
Solution:
Relation between volume and temperature in adiabatic expansion is
T
1
V
1
γ
−
1
=
T
2
V
3
γ
−
1
Here,
T
2
=
T
1
2
and
V
2
=
2
V
1
So,
T
1
V
1
γ
−
1
=
T
1
2
(
2
V
1
)
γ
−
1
.
⇒
1
=
1
2
.2
γ
−
1
⇒
2
=
2
y
−
1
⇒
γ
−
1
=
1
or
γ
=
2
© examsnet.com
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