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TS EAMCET 2016 Code A Solved Paper
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© examsnet.com
Question : 47
Total: 160
The equation of the pair of straight lines through the point
(
1
,
1
)
and perpendicular to the pair of straight lines
3
x
2
−
8
x
y
+
5
y
2
=
0
is
5
x
2
+
8
x
y
+
3
y
2
−
14
x
−
18
y
+
16
=
0
5
x
2
+
8
x
y
+
3
y
2
−
14
x
−
18
y
+
16
=
0
5
x
2
−
8
x
y
+
3
y
2
−
18
x
−
14
y
+
32
=
0
5
x
2
−
8
x
y
+
3
y
2
−
14
x
−
18
y
+
32
=
0
Validate
Solution:
5
(
x
−
1
)
2
−
8
(
x
−
1
)
(
y
−
1
)
+
3
(
y
−
1
)
2
=
0
5
(
x
2
−
2
x
+
1
)
+
8
(
x
y
−
x
−
y
+
1
)
+
3
(
y
2
−
2
y
+
1
)
=
0
5
x
2
−
10
x
+
5
+
8
x
y
−
8
x
−
8
y
+
8
+
3
y
2
−
6
y
+
3
=
0
5
x
2
+
8
x
y
+
3
y
2
−
18
x
−
14
y
+
16
=
0
© examsnet.com
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