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TS EAMCET 2017 Code A Solved Paper
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© examsnet.com
Question : 29
Total: 160
If
x
2
a
2
+
y
2
b
2
=
1
then
d
2
y
d
x
2
=
−
b
4
a
2
y
3
b
2
a
y
2
−
b
3
a
2
y
3
b
3
a
2
y
2
Validate
Solution:
Let us consider
x
=
a
cos
θ
⇒
d
x
d
θ
=
−
a
sin
θ
(i)
y
=
b
sin
θ
⇒
d
y
d
θ
=
b
cos
θ
(ii)
Divide equation (ii) by (i).
d
y
d
x
=
−
b
a
cot
θ
Again differentiate
d
y
d
x
with respect to x.
d
2
y
d
x
2
=
−
b
a
(
−
c
o
s
e
c
2
θ
)
d
θ
d
x
=
b
cos
e
c
2
θ
−
a
2
sin
θ
=
−
b
a
2
sin
3
θ
=
−
b
4
a
2
y
3
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