ms−1 Speed of body be vx along X-axis and vy along Y-axis after covering a displacement sx of 6m. Now, as we know that, v2−u2=2as and for displacement along X-axis vx2−ux2=2axsx ⇒vx2−16=2×4×6 ⇒vx=√48+16 ⇒vx=√64=8ms−1 ∴vx=8
∧
i
ms−1 Now, Since, v=u+at ∴t=
vx−ux
ax
where, t is time taken. ∴t=
8−4
4
=2s Again vy=uy+ayt ∴vy=0+4×1 =4ms−1 ⇒vy=4
