y−5=m(x−3) . . . (i) Coordinate of A for y=0 x=3−
5
m
. . . (i) A(3−
5
m
,0) Coordinate of B for x=0 y=5−3m . . . (iii) B(0,5−3m) Eliminating m from Eqs. (ii) and (iii), we get (x−3)(y−5)=15 ⇒xy−5x−3y=0 or 5x−xy+3y=0 Comparing with ax+2hxy+by=0, we get a=5,h=