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TS EAMCET 4 May 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 117
Total: 160
An active nucleus decays to one-third
(
1
3
)
in 20 His. The fraction of original activityremaining after 80 His is
1
16
1
81
1
36
1
54
Validate
Solution:
The decay equation is given by,
N
1
=
N
0
exp
(
−
λ
t
1
)
1
3
=
e
(
−
20
λ
)
e
20
λ
=
3
The decay equation is given by,
N
2
=
N
0
exp
(
−
λ
t
2
)
N
0
N
2
=
(
e
20
λ
)
4
N
2
=
1
3
4
N
0
N
2
=
N
0
81
© examsnet.com
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