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TS EAMCET 4 May 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 4
Total: 160
Let A =
[
1
6
−
1
3
−
1
6
−
1
3
2
3
1
3
−
1
6
1
3
1
6
]
. If
A
2016
l
+
A
2017
m
+
A
2018
n
=
1
α
A , for every l , m , n ∊ N , then the value of α is
1
6
1
3
1
2
2
3
Validate
Solution:
Consider the matrix.
A
=
[
1
6
−
1
3
−
1
6
−
1
3
2
3
1
3
−
1
6
1
3
1
6
]
The above matrix can be simplified as,
A
=
6
[
1
−
2
−
1
−
2
4
2
−
1
2
1
]
Now,
A
P
=
A
∀
∈
N
So,
A
20161
=
A
2017
m
=
A
2018
n
=
A
∀
1
,
m
,
n
∈
N
Therefore,
A
2016
I
+
A
2017
m
+
A
2018
n
=
3
A
1
α
A
=
3
A
α
=
1
3
© examsnet.com
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