Given, mass number, M1=M Initial volume, V1=V Final mass number, M2=2M As we know that, R=R0A1∕3 ⇒R∝A1∕3 . . . (i) where, R0= radius of nucleus and A= mass number. Since, volume V=
4
3
πR3 . . . (ii) ⇒R∝(V)1∕3 Now, from Eqs. (i) and (ii), we get ⇒R∝A1∕3∝V1∕3 ⇒