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TS EAMCET 5-Aug-2021 Shift 1 Question Paper
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© examsnet.com
Question : 9
Total: 160
If
x
=
4
5
+
3
5
i
,
y
=
√
3
√
8
−
√
5
√
8
i
, then
(
x
2
+
1
x
2
)
(
y
2
−
1
y
2
)
=
−
7
√
3
5
√
5
i
7
125
i
7
√
3
5
√
5
i
√
15
√
8
i
Validate
Solution:
👈: Video Solution
x
=
4
5
+
3
i
5
,
y
=
√
3
√
8
−
√
5
√
8
i
(
x
2
+
1
x
2
)
(
y
2
−
1
y
2
)
=
[
(
x
+
1
x
)
2
−
2
]
(
y
−
1
y
2
)
|
x
|
=
1
=
|
y
|
x
x
=
1
=
y
y
]
∴
[
(
x
2
+
x
2
)
(
y
2
−
y
2
)
[
(
x
+
x
)
2
−
2
x
x
]
(
y
+
y
)
(
y
−
y
)
[
(
8
5
)
2
−
2
]
(
2
√
3
√
8
)
(
−
2
√
5
√
8
)
i
+
14
25
×
(
−
√
15
2
i
)
=
−
7
√
3
5
√
5
i
© examsnet.com
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