Given, Let, mass of object A,mA=20kg Mass of object B,mB=200kg Initial speed of A,uA=20m∕s and initial speed of B,uB=10m∕s After collision, Final speed of A and B be vA and vB where, vA=−10m∕s. By using law of conservation of momentum, ‌mAuA+mBuB‌‌=mAvA+mBvB ⇒‌20×20+200×10‌‌=20(−10)+200vB ⇒‌400+2000‌‌=−200+200vB ⇒‌200vB‌‌=2600 ⇒‌vB‌‌=13ms−1